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http://upload.lsforum.net/users/public/e54701Untitledg52.jpg i) find the equivalent resistance at the end of e and f ii)find the equivalent resistance at the end of d and f
最佳解答:
(i) Consider the loop abcd, we have two 1-ohm resistors in series and then parallel with another 1-ohm resistor. Equivalent resistance = 1x2/(1+2) ohms = 2/3 ohm = 0.6667 ohm Hence, in loop ecdf, equivalent resistance = (1 + 0.6667 + 1) ohms = 2.6667 ohms Final equivalent resistance at ef = 2.6667 x 1/(2.6667+1) ohm = 0.727 ohm (ii) The circuit is similar to the one in (i) Equivalent resistance between cd = 1x2/(1+2) ohm = 0.6667 ohms Equivalent resistance between dcef = (0.6667 + 1 + 1) ohms = 2.6667 ohms Total equivalent resistance between df = 1 x 2.6667/(1+2.6667) ohm = 0.727 ohm
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resistance
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發問:http://upload.lsforum.net/users/public/e54701Untitledg52.jpg i) find the equivalent resistance at the end of e and f ii)find the equivalent resistance at the end of d and f
最佳解答:
(i) Consider the loop abcd, we have two 1-ohm resistors in series and then parallel with another 1-ohm resistor. Equivalent resistance = 1x2/(1+2) ohms = 2/3 ohm = 0.6667 ohm Hence, in loop ecdf, equivalent resistance = (1 + 0.6667 + 1) ohms = 2.6667 ohms Final equivalent resistance at ef = 2.6667 x 1/(2.6667+1) ohm = 0.727 ohm (ii) The circuit is similar to the one in (i) Equivalent resistance between cd = 1x2/(1+2) ohm = 0.6667 ohms Equivalent resistance between dcef = (0.6667 + 1 + 1) ohms = 2.6667 ohms Total equivalent resistance between df = 1 x 2.6667/(1+2.6667) ohm = 0.727 ohm
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